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Home » Time, \( t = 15 \) years - Coaching Toolbox

Time, \( t = 15 \) years - Coaching Toolbox

📅 May 3, 2026 👤 scraface

May 03, 2026

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A technology consultant is analyzing server costs. A cloud provider ch...
2nd: 180 > 100, so already exceeds in month 1?
But 100 < 180, so second is more expensive from start.
Make first provider cheaper base but same rate.
To have first cheaper at low m, but second catches up.
But question: when second exceeds first.
But this is for m > 6, so up to m = 16
But we want first to be cheaper first, then second catches.
Set in low m: but with inquiry, perhaps:
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