tyler perry straw

Sun, 03 May 2026 16:04:03 +0000

Ex 6.2, 1 Find the cube root of each of the following numbers by prime factorisation method. (x) 91125We see that 91125 = 3 3 3 3 3 3 5 5 5 Since 3 & 5 occur in triplets . Prime Factors of 91125 are all the prime numbers that when multiplied together equal 91125. The process of finding the Prime Factors of 91125 is called Prime Factorization of 91125. To get the Prime Factors of. The prime factorization of 91125 is: $$ 91125 = 3\cdot3\cdot3\cdot3\cdot3\cdot3\cdot5\cdot5\cdot5 $$ Which is the same as : $$ 91125 = 3^ {6}\cdot5^ {3} $$ Explanation The prime factorization of a positive integer is a list of the integer's prime factors, together with their multiplicities; the process of determining these factors is called integer factorization. Type the number.