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📰 Actually, \( u + rac{1}{u} = 2 \) implies \( u = 1 \) (since for complex \(u\), this only holds if \(|u| = 1\) and conjugate symmetry, but equality to 2 forces \(u = 1\) in \( \mathbb{C} \) only if real and positive, but let's solve generally). 📰 Set \( u + rac{1}{u} = 2 \). Multiply by \(u\): \( u^2 - 2u + 1 = 0 \Rightarrow (u - 1)^2 = 0 \Rightarrow u = 1 \), still. 📰 So \( rac{z + w}{z - w} = 1 \Rightarrow z + w = z - w \Rightarrow 📰 Fox Network Television 1577357 📰 50 Secret Steps To Read Receipts In Outlookyouve Never Seen Before 6737982 📰 Liteblue Secrets You Never Knew Could Transform Your Look 1151676 📰 Umar The Untold Story Behind His Breakthrough Success You Wont Believe 4384453 📰 Grass Pokemon With This Type 4136385 📰 Is Crazyb Game The Ultimate Hidden Gem Youve Been Searching For 5839431 📰 Penn State Wins Bitter Battle After Rivalry Tournaments Turn Deadly 1917280 📰 The Untold Truth About Harry Osborn That Explains His Rise And Fall 6451630 📰 High Interest Yield Savings Account 8158392 📰 When Does No Taxes On Overtime Start 5606516 📰 Travel Insurance Companies 2553368 📰 Fashionistas Reveal Velvet Cloth Dresses Are The Hottest Trend Of 2024Dont Miss Out 6700971 📰 Iowa Shock Rutgers In Instant Gamebreaking Thriller 7530307 📰 Marvel Avengers Characters 7424724 📰 Proving Sprinters Are Born Here Join The Epic Sprinting Game Adventure Now 8482870