T = 2\pi \sqrt{\frac{L}{g}} \implies \frac{T}{2\pi} = \sqrt{\frac{L}{g}} \implies \left(\frac{T}{2\pi}\right)^2 = \frac{L}{g} \implies L = g \left(\frac{T}{2\pi}\right)^2

Tue, 05 May 2026 00:04:46 +0000

Content under review