A) $ \frac{2\sqrt{3}}{3} \cdot \frac{r^2}{\text{Area}} = 1 $ → Area ratios: $ \frac{2\sqrt{3} s^2}{6\sqrt{3} r^2} = \frac{s^2}{3r^2} $, and since $ s = \sqrt{3}r $, this becomes $ \frac{3r^2}{3r^2} = 1 $? Corrección: Pentatexto A) $ \frac{2\sqrt{3}}{3} \cdot \frac{r^2}{\text{Area}} $ — but correct derivation: Area of hexagon = $ \frac{3\sqrt{3}}{2} s^2 $, inscribed circle radius $ r = \frac{\sqrt{3}}{2}s \Rightarrow s = \frac{2r}{\sqrt{3}} $. Then Area $ = \frac{3\sqrt{3}}{2} \cdot \frac{4r^2}{3} = 2\sqrt{3} r^2 $. Circle area: $ \pi r^2 $. Ratio: $ \frac{\pi r^2}{2\sqrt{3} r^2} = \frac{\pi}{2\sqrt{3}} $. But question asks for "ratio of area of circle to hexagon" or vice? Question says: area of circle over area of hexagon → $ \frac{\pi r^2}{2\sqrt{3} r^2} = \frac{\pi}{2\sqrt{3}} $. But none match. Recheck options. Actually, $ s = \frac{2r}{\sqrt{3}} $, so $ s^2 = \frac{4r^2}{3} $. Hexagon area: $ \frac{3\sqrt{3}}{2} \cdot \frac{4r^2}{3} = 2\sqrt{3} r^2 $. So $ \frac{\pi r^2}{2\sqrt{3} r^2} = \frac{\pi}{2\sqrt{3}} $. Approx: $ \frac{3.14}{3.464} \approx 0.907 $. None of options match. Adjust: Perhaps question should have option: $ \frac{\pi}{2\sqrt{3}} $, but since not, revise model. Instead—correct, more accurate: After calculation, the ratio is $ \frac{\pi}{2\sqrt{3}} $, but among given:

Mon, 04 May 2026 11:57:23 +0000

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