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📰 Solution: This is a multinomial probability problem. Let $ X = (X_S, X_P, X_F) $ be the counts of each outcome in 12 independent trials, with probabilities $ p_S = 0.4 $, $ p_P = 0.3 $, and $ p_F = 0.3 $. The probability mass function of a multinomial distribution gives: 📰 P(X_S = 5, X_P = 4, X_F = 3) = rac{12!}{5! \cdot 4! \cdot 3!} \cdot (0.4)^5 \cdot (0.3)^4 \cdot (0.3)^3 📰 First, compute the multinomial coefficient: 📰 A Company Has A Revenue Of 10000 In January Each Subsequent Month The Revenue Increases By 5 Compared To The Previous Month What Is The Companys Revenue At The End Of March 9004352 📰 The Ultimate Guide To Gundam Unicorn You Dont Want To Miss These Amazing Features 7033420 📰 Youll Never Look At Games The Same Wayheres What Hidden Game Playing Reveals 2880137 📰 Heir Of Fire 7766787 📰 Sat Testing Near Me 3374097 📰 You Wont Believe These Mortgage Rate Jumps In November 2025Insiders Reveal Why 6407217 📰 Inside The Secret To Finding Your Exact Look Alike Guaranteed 3640520 📰 Highest Savings Interest Rate 2950874 📰 Change Your Desktop Wallpaper Instantly With These Revolutionary Windows 10 Tricks 5677100 📰 This Wire Ampacity Chart Will Change How You Wire Any Circuit Forever 3217988 📰 First 1000 Equiv 8 Pmod16 So 5000 5 Cdot 1000 Equiv 5 Cdot 8 40 Equiv 8 Pmod16 Since 40 2 Cdot 16 8 6433058 📰 Kora Tv Exposes The Dark Truth Behind Fashions Favorite Channel 295470 📰 Heisman Voted 9150559 📰 Kia Sorento 2020 3091368 📰 Robert Sheehan 3412594