\binom{4}{2} \left(\frac{1}{3}\right)^2 \left(\frac{2}{3}\right)^2 = 6 \cdot \frac{1}{9} \cdot \frac{4}{9} = \frac{24}{81} = \frac{8}{27}.

Wed, 06 May 2026 12:31:49 +0000

Content under review