We need 18n = multiple of 45 → n divisible by 5/ gcd(2,5)=5 → n multiple of 5? Actually: 18n divisible by 45 → n divisible by 45 / gcd(18,45) = 45/9 = 5 → yes, n divisible by 5.

Wed, 06 May 2026 17:31:26 +0000

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