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📅 May 3, 2026 👤 scraface

May 03, 2026

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📝 Recent Posts

\boxed{\frac{2}{27}}
Question:** A retired scientist is mentoring students on geometric pro...
Set the area equal to \( 36\sqrt{3} \):
\frac{1}{4} s^2 = 36 \Rightarrow s^2 = 144 \Rightarrow s = 12 \, \text...
New side length after reduction:
s' = 12 - 2 = 10 \, \text{cm}
A' = \frac{\sqrt{3}}{4} (10)^2 = \frac{\sqrt{3}}{4} \times 100 = 25\sq...
\Delta A = 36\sqrt{3} - 25\sqrt{3} = 11\sqrt{3} \, \text{cm}^2
\boxed{11\sqrt{3} \, \text{cm}^2}
\]1. A circle has a radius of 7 cm. Calculate its circumference and th...

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